docs: 将仓库代码注释统一为中文
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@@ -226,13 +226,7 @@ _CURVE_MAX_REFINEMENT_EVALUATIONS = 8192
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def _refine_crossing(tree, left, right, ymin, ymax, budget=None):
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"""Adaptively check both halves of a crossing; None explicitly breaks a path.
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A visible midpoint is not a continuity proof. Accept a visible chord only
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when its midpoint error is within a quarter pixel; otherwise subdivide both
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halves. Depth, evaluation and floating-point limits always break unresolved
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intervals instead of joining them. Entirely off-screen triples can be culled.
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"""
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"""自适应检查路口的两半; None 明确中断了一条路径。可见的中点并不是连续性证明。仅当中点误差在四分之一像素以内时才接受可见弦;否则将两半细分。深度、求值和浮点限制总是打破未解决的间隔,而不是连接它们。完全不在屏幕外的三元组可以被剔除。"""
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remaining = _REFINE_MAX_EVALUATIONS
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if budget is None:
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budget = [_REFINE_MAX_EVALUATIONS]
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@@ -255,12 +249,11 @@ def _refine_crossing(tree, left, right, ymin, ymax, budget=None):
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values = (a[1], y, b[1])
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if all(math.isfinite(v) for v in values):
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if max(values) < ymin or min(values) > ymax:
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return [a, None, b] # No visible chord; do not connect across it.
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return [a, None, b] # 无可见和弦;不要通过它连接。
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error = abs(y - (a[1] / 2 + b[1] / 2))
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if any(ymin <= v <= ymax for v in values) and error <= tolerance:
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return [a, mid, b]
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# Refine either side of a nonfinite midpoint too: dropping the whole
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# interval would erase valid branches between the original samples.
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# 也优化非有限中点的任一侧:删除整个间隔将擦除原始样本之间的有效分支。
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first = refine(a, mid, depth + 1)
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second = refine(mid, b, depth + 1)
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return first + second[1:]
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@@ -309,7 +302,7 @@ def _sample_segments(
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continue
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if prev_y is not None:
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refined = _refine_crossing(tree, (prev_x, prev_y), (x, y), ymin, ymax, budget)
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samples = refined[1:] # The previous endpoint is already in points.
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samples = refined[1:] # 前一个端点已经以点为单位。
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else:
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samples = [(x, y)]
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for sample in samples:
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